Question

father is 30 years older than his son. In 12 years, the man will be three times as old as his
on. Find their present ages​

Answer 1

Answer:

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Step-by-step explanation:

Let son's age be x.

So fathers age will be x + 30.

ATQ - 3(x+12) = x + 30 +12

          3x + 36 = x + 42

          3x - x = 42 - 36

          2x = 6

          x = $\frac{6}{2}$

          x = 3

Fathers age = 3 + 30 = 33 years

Sons age = 3 years

Answer 2

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• Father is 30 years old than his son
• In 12 years the man will be 3 times his son

______________________

$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

• present age of son and father = ??

______________________

$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

⠀⠀⠀⠀

Let the son's age be x

⠀⠀

Therefore :-

⠀⠀⠀⠀

Father's age = 30 + x

⠀⠀⠀⠀

After 12 years :-

⠀⠀⠀⠀

Son's age = x + 12

⠀⠀⠀⠀

Father's age = x + 12 + 30

⠀⠀⠀⠀

• ATQ :-

⠀⠀

3 ( x + 12 ) = x + 12 + 30

⠀⠀⠀⠀

3x + 36 = x + 12 + 30

⠀⠀⠀⠀

3x + 36 = x + 42

⠀⠀⠀⠀

3x - x = 42 - 36

⠀⠀⠀⠀

2x = 6

⠀⠀⠀⠀

x = 6 / 2

⠀⠀

x = 3

⠀⠀⠀⠀

Father's age = x + 30 = 30 + 3 = 33 years

______________________

$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

• Son's age = 3 years
• Father's age = 33 years