Question

Father is 30 years older than his son .one year ago , he was four time s old s his son .find their present ages.

Answer 1

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⭐$\textbf {Hey there, here is the solution.}$

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⭐$\textbf {Let the son be x years old.}$

⭐$\textbf {His father is x + 30.}$

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⭐$\textbf {One years ago.}$

⭐$\longrightarrow \textbf {Son = x - 1}$

⭐$\longrightarrow \textbf {Father= x + 30 - 1 = x + 29}$

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$\textbf {One year ago, the father is 4 times as old as his son}$

⭐$\textbf {x + 29 = 4(x - 1) }$

⭐$\textbf {x + 29 = 4x - 4 }$

⭐$\textbf {3x =33 }$

⭐$\textbf {x =11 }$

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⭐$\textbf {Find their age: }$

⭐$\textbf {Son = x = 11 }$

⭐$\textbf {Father = x + 30 = 11 + 30 = 41}$

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⭐$\textbf {Answer: Son is 11 years old and father is 41 years old}$

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⭐$\textbf {Cheers}$

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Answer 2

Answer:

Step-by-step explanation: