Question

father is 3time as old As his son after 12year his age will be twice as that of his son then find their present age

Answer 1

let son 's age be x
then his father's age = 3x
after 12 years
son's age = x+12
father's age = 3x +12.
A/Q
3x+ 12 = 2(x + 12)
3x+ 12 = 2x + 24
3x - 2x = 24 - 12
x = 12
At present
son's age = x = 12 years
father's age = 3x = 3 × 12 = 36 years.

Answer 2

Let fathers age be x
=> sons age be y

X = 3y x+12 = 2(y+12)
x+12 = 2y+24
x-2y = 12

=> 3y-2y = 12
y = 12

=> x = 3y
= 3 x 12
= 36

Therefore fathers age = 36
Sons age = 12