Question

father is 4 times as old as his son. After 4 years,he will be three times as old as his son. What are their present ages? *

Answer 1

Answer:

Step-by-step explanation:

present age

let the sons age be x

then fathers age= 4x

after 4years

sons age= x+4

fathers age = 4x+4

but given after 4 years

sons age = x+4

fathers age = 3(x+4)

4x+4 = 3(x+4)

4x+4 = 3x+ 12

4x-3x=12-4

x=8

4x= 4*8

   =32

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Answer 2

Hope it helps....

Answer ➡

Present age,

let the son's age be x

and father's age= 4x

After 4years,

sons age= x+4

fathers age = 4x+4

But given after 4 years,

Son's age = x+4

Father's age = 3(x+4)

According to statement. ( A.T.S )

4x+4 = 3(x+4)

4x+4 = 3x+ 12

4x-3x=12-4

x=8

Therefore,

Son's age is x = 8.

And Father's age is 4x= 4×8 = 32.

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