Math, asked by kamranansari9, 10 months ago

father is 5 times as old as his son. After 15 years he will be two times as old as his son. Father's present age is.​

Answers

Answered by Anonymous
10

Step-by-step explanation:

Father’s age, now = F, son’s age now = S.

F = 5S …(1)

F+15 = 2(S+15), or

F = 2S+30–15 = 2S+15 …(2)

Equate (1) and (2),

5S = 2S+15, or

3S = 15, or S = 5 and F - 25.

The father is 25 years now.

Answered by Anonymous
7

Step-by-step explanation:

Step-by-step explanation:

Father’s age, now = F, son’s age now = S.

F = 5S …(1)

F+15 = 2(S+15), or

F = 2S+30–15 = 2S+15 …(2)

Equate (1) and (2),

5S = 2S+15, or

3S = 15, or S = 5 and F - 25.

The father is 25 years now.

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