Father is 5 times as old as his son. After two years the father will be 4 times as old as his son then present age of father is?
Answers
Answered by
3
let the present age of son be x years,
therefore, father's age =5x
son's age after 2yrs = x+2
father's age after 2yrs = 5x +2
ATQ
5x+2= 4(x+2)
5x +2 = 4x + 8
5x-4x = 8-2
x= 6
son's age = 6yrs
therefore, father's age = 5*6yrs =30yrs
therefore, father's age =5x
son's age after 2yrs = x+2
father's age after 2yrs = 5x +2
ATQ
5x+2= 4(x+2)
5x +2 = 4x + 8
5x-4x = 8-2
x= 6
son's age = 6yrs
therefore, father's age = 5*6yrs =30yrs
Similar questions