Question

father is 6 times old as old as his son four years hence he will be 4 times as old as his son at that time find their present ages

Answer 1

Heya!
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↪Let age of Son be x years

↪Then age of Father 6x years


⭐Four Years Hence ,


( 6x + 4 ) = 4 ( x + 4 )


=> 6x + 4 = 4x + 16

=> 6x - 4x = 16 - 4

=> 2x = 12


=> x = 6
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◼Age of Son is 6 years !

⬛Age of Father is 36 years !


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Answer 2

Let son's age = X

Father's age = 6x

Four years later

son's age = X+4

father's age = 6x+4

According to the given question

6x+4 = 4(X+4)

6x+4 = 4x+16

6x - 4x = 16 - 4

2x = 12

X = 12/2

X = 6.

present age of son X = 6 years

present age of father 6x = 6(6) = 36 years.