Question

Father is aged 3 times more than his son alok.After 8 years he would be 2 and a half times of alok's age. After further 8 years ,how many times would he be of alok's age?

Answer 1

hey

___________

alok age be x years

father be 3x+x years

•after 8 years

alok age = x+8 years

fathers age = 2 whole 1/2 years of alok

a/q to question

4x+8=2 whole 1/2(x+8)

4x+8=5/2x+5/2×8

4x-5/2x = 20-8

8x-5x/2=12

3x/2=12

x=12×2/3

x=8

after furhter 8 years

alok age = x+8+8

=8+8+8=24Yrs

alok father age= 4x+8+8

4×8+8+8= 48

alok father will be 2 times alok age

hope helped

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Answer 2

Hey mate !!

solutions :-

Let
Alok age be x years

Father be 3x+x years


A/q

After 8 years

Alok age = x+8 years

Again

Fathers age = 2 whole 1/2 years of alok.



A/q

4x+8=2 whole 1/2(x+8)

4x+8=5/2x+5/2×8

4x-5/2x = 20-8

8x-5x/2=12

3x/2=12

x=12×2/3

x=8


➡After 8 years = alok age = x+8+8 =8+8+8
=24 Years


➡Alok father age= 4x+8+8 = 4×8+8+8= 48 year

Hence

Alok father will be 2 times of alok age


@Anushka