Question

Father is aged three times more than his son. After 4 years, he would be two and a half times of sons age. After 10 years, how many times would he be of sonsage?

Answer 1

hey mate your answer is similar to this

let ronit age is 'x' ywears.so his father's age is 3x.

after 8 years,

therefore,ronit age is 'x+8' his fathers age is 2 and half times ronit age

so

3x+8=5/2(x+8)

..x=24 fathers age =3(24)=72

after 8 years ronit age=32 and fathers age is 80

again after 8 years ronit age=40 andfathers age is 88

therefore fathers age is 2.2 times of ronit age.

THANK YOU.

Answer 2

Hi mate!

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