Math, asked by naeemofficial8844, 11 months ago

Father is aged three times more than his son rohit. After 8 yrs, he would be two and a half times of rohit’s age. After further 8 yrs, how many times would he be of rohit’s age?

Answers

Answered by lyonskm99
0

F=3R.

After 8 yrs.

F+8=5/2(R+8)

2F+16=5R+16

2(3R) +16=5R+40

R=24 ROHIT

Aft further 8

Rohit == 24+8=32

Father == 24*3+8=80

80/32====5/2

The father would 5/2 times Rohit’s age.

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