Question

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
A.2 times
B.21/2 times
C.23/4 times
D.3 times

Answer 1

Let son's age be xx

Then father's age = 3x3x

After 8 years,

3x+8=52(x+8)3x+8=52(x+8) ( since 212=52212=52 )

Multiplying both sides by 2,

2(3x+8)=5(x+8)2(3x+8)=5(x+8)

6x+16=5x+406x+16=5x+40

6x−5x=40−166x−5x=40−16

x=24x=24

So son's age is 24 and father's age is 72.

After 16 years ( since the question is asked as a further 8 years ),

son will be 40 ( 24 + 16 ) and father will be 78 ( 72 + 16 ).

Hence ratio = 7840=3920=119207840=3920=11920