Question

father is aged three times more than his son ronit. after 8 years, he would be two and a half times of ronit's age. after further 8 years, how m

Answer 1

Let Age of father be x years

Let age of son (Ronit) be y years

x= 3y

After 8 years

x+8= 5/2(y+8)

3y+8= 5y+40/2

6y+16= 5y+40

y= 24 years

x= 72 years