Question

Father is four times the age of Daughter.after 18 years he will b twice the age of daughter.find their present ages

Answer 1

Answer:

THE PRESENT AGES OF THE DAUGHTER AND THE FATHER ARE 9 YEARS AND 36 YEARS RESPECTIVELY

Step-by-step explanation:

LET THE PRESENT AGES OF THE DAUGHTER AND THE FATHER BE X AND 4X

AFTER 18 YRS. AGES OF THE DAUGHTER AND THE FATHER WILL  BE

X+18 AND 4X+18

ACCORDING TO QUESTION:

2(X+18)=4X+18

2X+36=4X+18

4X-2X=36-18

2X=18

X=18/2=9

SO

THE PRESENT AGES OF THE DAUGHTER AND THE FATHER ARE:

X=9 YRS

4X=4*9=36 YRS.