Father is four times the age of his daughter. If after 5 years, he would be threee times of daughter’s age, then further after 5 years, how many times he would be of his daughter’s age?
Answers
Let the daughter's age be x and father's age be 4x.
So as per question, 4x + 5 = 3(x + 5). So x = 10.
Hence present age of daughter is 10 years and present age of father is 40 years.
So after 5 + 5 = 10 years, daughter age would be 20 years and father’s age would be 50 years.
Hence father would be 50/20 = 2.5 times of daughter’s age.
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Answer:
Given,
age of father = four times the age of daughter
after 5 years, father's age = 3 times of age of daughter
to find: further after 5 years, how many times he would be of his father's age
Explanation:
let the age of daughter = x
father's age = 4x
after 5 years,
age of daughter = x +5
age of father = 3(x+5) = 4x +5
3x + 15 = 4x + 5
4x - 3x = 15-5
x = 10
age of daughter = x +5 = 10+5 = 15 years
age of father = 3(x+5) = 3(10+5) = 3(15)
age of father = 45 years
after further 5 years,
age of daughter = x + 5
age of daughter = 15+5=20 years
age of father = 45 +5 = 50 years
age of father = 5/2 times of age of daughter
age of father = 2.5 times the age of daughter