Math, asked by Rashmi46788, 10 months ago

Father is four times the age of his daughter. If after 5 years, he would be threee times of daughter’s age, then further after 5 years, how many times he would be of his daughter’s age?​

Answers

Answered by Shrutikulashri
7

Let daughter age be x.

A. T. Q

Father age = 4x

After 5 year

Daughter age = x+5

Father age = 4x +5

A. T. Q

4x+5=3(x+5)

x =10

Present age of daughter =10

Present age of father = 40

So after 5+5 years

daughter age = 20

Father age = 50

Therefore father will be 50 /20 = 2.5 times the daughter age.

Hope this will help you... :)

Answered by mikun24
8

Answer:

hy mate

here's your answer

Step-by-step explanation:

From this question we can set up a system of equations, taking f=father’s initial age and d=daughter’s initial age:

1) f=4d

2) f+5=3(d+5)

Substituting (1) into (2):

4d+5=3d+15

Rearranging gives:

d=10

Substituting back into (1) gives:

f=40

Checking in (2):

45=3 x 15

So in a further 5 years the father will be 50 and the daughter will be 20. So he will be 50/20=2.5 time her age

Hope it helps you

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