Question

Father is six times as old as his son. Five years hence he will be four times as old as his son. Find their present ages.

Answer 1

Answer:

let son's age be x.

father= 6x.

after five years.

son = x+5.

father= four times son's age.

4(x+5)

father's age can also be 6x+5 from above equation.

4(x+5)= 6x+5

4x+20= 6x+5

6x-4x= 20-5

2x = 15

x= 7.5 years.

there son's present age=x= 7.5 years.

father= 6x= 7.5×6= 45 years.

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Answer 2

Correct Question

Father is six times as old as his son. Four years hence he will be four times as old as his son.

Find their present ages

To find

Find their present ages

Solution

✞ According to the given condition

✒ Let the son age be x year then his father age be 6x year

✒ After 4 years

• Son age = x + 4
• Father age = 6x + 4

➨ 4(x + 4) = 6x + 4

➨ 4x + 16 = 6x + 4

➨ 16 - 4 = 6x - 4x

➨ 12 = 2x

➨ x = 12/2 = 6

${\underline{\boxed{\bf{Present\:age\:of\:son=6year}}}}$

$\mathtt{\underline{\boxed{\bf{Present\:age\:of\:father=6x=36year}}}}$