Math, asked by guptasameer, 1 year ago

father is six times as old as his son . ten years ago he was five timeshis sons age. their present ages are​

Answers

Answered by aka01
0

father is six times as old as his son . ten years ago he was five timeshis sons age. their present ages are

Answered by Abhilipsanayak543
0

Answer:

Step-by-step explanation:

Let age of son be x .

Let the age of father be 6x as he is six times older than his son.

So, x+6x

Before 10 years

Son age was x and his father was 5x as he was five times older than him.

So According to the question

=> x+6x-10 = x+5x

=> x+6x-x-5x = 10

=> x-x+6x-5x = 10

=> 6x-5x = 10

=> x = 10

So age of son is 10 years

Age of father will be 6x = 6×10 = 60 years

So present age of son is 10 years and the age of his father is 60 years old.

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