father is three times as old as his son if the difference of their age is 24 find their present age
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Answered by
5
let son age = x
father's age= 3x
A/C to que
3x-x= 24
= 2x= 24
= x= 12
son age = 12 years old
father's age= 3× 12 = 36 year old
Answered by
1
so the father age be x =36years
and son age be y = 12 years
Step-by-step explanation:
Let the present age of the father be 'x' years and that of son be 'y' years.
According to the question,
Condition I,
Father is three times as old as his son,
or,x=3y - (i)
Condition II,
The difference of their ages is 24 years,
or,x−y=24
Put the value of x from equation i in equation ii, we get,
or,3y−y=24
or,2y=24
or,y=242
∴y=12
Now,
Put the value of y in equation (i), we get,
or,x=3×12
∴x=36
so , the father age be x =36years
and son age be y = 12 years
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