Math, asked by devanshu2837, 1 month ago

father is twice as old as his daughter. If 20 years ago, the age of the father was 10 times the age of the daughter, what is the present age of the father?

40 years
32 years
33 years
45 years
22 years

Answers

Answered by cjha33976
2

Answer:

therefore, father's age is 45 years. Originally Answered: The father's age is 4 times the age of his son's now. 10 years ago, the father was 10 times as old as his son

Answered by devanshu1234321
19

QUESTION:-

father is twice as old as his daughter. If 20 years ago, the age of the father was 10 times the age of the daughter, what is the present age of the father?

40 years

32 years

33 years

45 years

22 years

EXPLANATION:-

Let the present age of the father be 2x

So, the present age of the daughter = x

According to the question,  

⇒2x-20 = 10(x-20)

⇒2x-20 = 10x – 200

⇒8x = 180

⇒x= 22.5

Thus, the present age of father = 22.5 × 2 = 45 years

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