Question

father's age is 3 time the sum of age of two children.after 5 years his age will be twice the sum of age of two children.find the age of fathes
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Answer 1

Answer:

Father's age is 45 yrs

Step-by-step explanation:

Let the present ages of the children be x and y and that of the father be z

given

$3(x + y) = z \\ (x + y) = \frac{z}{3} \: \: \: \: \: \: \: \: \: \: \: (1)$

Also

$2(x + 5 + y + 5) = z + 5 \\ 2(x + y) = z - 15 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (2)$

using (1) in (2) we have

$2 \times \frac{z}{3} = z - 15 \\ 2z = 3z - 45$

$z = 45$

Answer 2

Step-by-step explanation:

Let the age of father be x years and sum of the ages of his children by y years.

After 5 years,

Father's age = (x + 5) years

Sum of ages of his children = (y + 10) years

From the given information, we have:

x = 3y ...(1)

and x + 5 = 2(y + 10)

x - 2y = 15 ...(2)

From (1) and (2), we have,

3y - 2y = 15 y = 15

x = 3y = 45

Father's age = 45 years

MARK AS BRAINLIEST....