Father's age is 3 times the age of his two children's age.After 5 years his age will be twice the sum of the ages of 2 children find the age of children's and father
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his children will be x and father will be y
2x+3y +5=2x +2y
2x +3y=2x+2y-5
2x cancelled
3y= 2y-5
3y-2y=-5
y=-5
2x+3y +5=2x +2y
2x +3y=2x+2y-5
2x cancelled
3y= 2y-5
3y-2y=-5
y=-5
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