Father's age is 3 times the sum of age of 2 children.after 5 years his age will be twice the sum of age of 2 children find the age of father
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age of 2 children= x+y
father age= 3(x+y)
after 5 year age of 2 children= ((x+5)+(y+5))=(x+y+10)
after 5 year father age=2(x+y+10)
then father age 3(x+y)+5= 2(x+y+10)
x+y=15
present age of father= 2(x+y+10)= 50
father age= 3(x+y)
after 5 year age of 2 children= ((x+5)+(y+5))=(x+y+10)
after 5 year father age=2(x+y+10)
then father age 3(x+y)+5= 2(x+y+10)
x+y=15
present age of father= 2(x+y+10)= 50
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