Question

Father's age is 3 times the sum of ages of his two children. After 5 years his age will be twice the
sum of ages of two children. Find the age of father.

Answer 1

Let the sum of present ages of children be a

Present age of father = 3a

According to question,

3a + 5 = 2(a +5 + 5)

=> 3a + 5 = 2a + 20

=> a = 15

Now,

b = 3 × 15

Present age of father = 45 years

Answer 2

ANSWER:

ASSUMPTIONS:

Let the age of father be x years.

Let the sum of ages of his two children be y years.

According to the statement, Father's age is 3 times the sum of ages of his two children.

x = 3y => Equation.1

Now the second statement, After 5 years his age will be twice the

After 5 years his age will be twice thesum of ages of two children.

x + 5 = 2 (y+5+5)

x + 5 = 2y + 10 + 10

x + 5 = 2y + 20

x = 2y + 20 - 5

x = 2y + 15

Substitute x=3y from equation 1.

3y = 2y + 15

3y - 2y = 15

y = 15

Now, substitute y=15 in equation.1

x = 3 × 15

x = 45

So, as per our assumptions we assumed father's age as x years.

The value of x on solving the equation is the age of father.

Therefore, age of father 45 years.