father's age is 3 times the sum of his two children sage after 5 years his age will be twice the sum of the ages of the two children find the age of the father
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let Father’s present age = x
Ages of the two sons = m & n
The sum of the ages of the sons = m+n = a
According to the question, father’s age is three times the sum of ages of his two sons.
=> x =3a — (1)
After five years, father’s age is x+5, and his sons’ ages are m+5 and n+5.
According to the question, father’s age is two times the sum of the ages of his two sons.
=> x+5 = 2(m+5+n+5)
=> x+5 = 2(m+n+10)
=> x+5 = 2(a+10)
=> 3a+5 = 2a+20 [From Eq1]
=> a = 15
Putting in Eq1, x = 3(15) = 45
Therefore, father’s age is 45 years.
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sahib31:
thamks bro
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above answer is right..ok
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