Question

father's age is 4 less than five times the age of his son and the product of their ages is 288.find the father's age​

Answer 1

Answer:

Step-by-step explanation:

Let, the age of the father = x

And, the age of the son = y

ATQ, x = 5y - 4

And, x*y = 288 ...... (1)

Putting the value of x in (1)

(5y-4)*y = 288

5y^2 - 4y = 288

5y^2 - 4y - 288 = 0

Now solve the following equation

Answer 2

Answer:

Step-by-step explanation:

Let the son’s age be x and father’s age be y

According to data ,

Father’s age(y) = 5x-4. .....(1)

Product of their ages is 288

xy = 288. ......(2)

Substituting 1 in 2

(x)(5x-4)=288

5x^2-4x=288

5x^2-4x-288=0

5x^2-40x+36x-288=0. (Splitting the middle term)

5x(x-8)+36(x-8)=0

(5x+36)(x-8)=0

Case 1

5x+36=0

x= -36/5

This is not possible because age cannot be negative

Case2

x-8=0

x=8

Therefore age is 8 years

father age is 5x-4

5(8)-4= 40-4

=36

Father’s age is 36 years