Math, asked by sameeranayeem24, 7 months ago

father's age is 4 times his son after 16 yrs will he be twice his son's age . find their present age

please respond​

Answers

Answered by mrsnarmadapatel
0

Let the age of the son be x years

Age of the father = 4x years

16 years later :-

Father's age = 4x + 16

Son's age = × + 16

According to the question:-

4x+16 = 2(x+16)

4x+16 = 2x+32

4x-2x = 32-16

2x = 16

x = 16/2

x = 8

Present age of son = x years = 8 years

Present age of father = 4x years = 4×8 years

= 32 years

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