Question

Father's age is 4 times the
age of his son now. 10 year age
father was 10 times as old as his son. What is the present age of father.​

Answer 1

Step-by-step explanation:

The father's age is 4 times the age of his son’s now. 10 years ago, the father was 10 times as old as his son. What is the present age of the father?

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While solving these kind of algebric equation problems be sure you have good imagination skills to figure out what steps to take while solving.

First let's look at the solution:

Let the present age of son be x

Then father's present age is 4x

Now,

According to question,

That is 10 years ago,

4x- 10 = 10 (x- 10)

4x -10=10x-100

100–10=10x-4x

90=6x

x=90/6

x=15

therefore,

Father=4x

=4*15

=60 years old

Answer 2

Answer:

First let's look at the solution:

Let the present age of son be x

Then father's present age is 4x

Now,

According to question,

That is 10 years ago,

4x- 10 = 10 (x- 10)

4x -10=10x-100

100–10=10x-4x

90=6x

x=90/6

x=15

therefore,

Father=4x

=4*15

=60 years old

Step-by-step explanation:

Explanation in detail:

In the first line of the question we see that the question is talking about present ages therefore to start this one off we need simple algebra .Suppose that the sons age was x . Therefore fathers age would be 4 times sons age that's 4x.

In the second phase it talks about past or simply 10 years before the present time, Here we need to make an idea that when we are talking about past our ages will be less than the present time. So, to get the age for past we need to subtract 10 years form present age in this scenario. Fathers age would be 4x-10 and son's age would be x-10.

Third step ,We now that to get the answer we need to equate things right? So as indicated in the question in past that's 10 years before the father was 10 times older then his son.

So its simple

4x-10= 10 *(x-10)

And then we can easily get the solution.