Father's age is equal to the sum of the ages of his five children. After 15 years, his age will be only
half of the sum of the children's ages. How old is the father ?
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Answer:
A father’s age is equal to the sum of the ages of his 5 children. In 15 years, his age will be half of the sum of their ages. How old is the father?
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Let us consider the age of the father x and the sum of ages of the 5 children as y.
At present,
x=y−−−−(i)
After 15 years,
Father’s age = x + 15
Sum of children’s ages = y + 5*15 (Because in the course of 15 years, each child will grow by 15 years)
x+15=1/2(y+5∗15)−−−−(ii)
Solving (i) and (ii), we get by substituting the value of x from (i) in (ii)
y+15=1/2(y+5∗15)
=>2y+30=y+75
=> y=45
which implies, x = 45
The age of the father is 45 years.
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Answer:
Let us consider the age of the father x and the sum of ages of the 5 children as y.
At present,
x=y−−−−(i)
After 15 years,
Father’s age = x + 15
Sum of children’s ages = y + 5*15 (Because in the course of 15 years, each child will grow by 15 years)
x+15=1/2(y+5∗15)−−−−(ii)
Solving (i) and (ii), we get by substituting the value of x from (i) in (ii)
y+15=1/2(y+5∗15)
=>2y+30=y+75
=> y=45
which implies, x = 45
The age of the father is 45 years.