Father's age is four times the son's age. ten years from now sons age will be half of the fathers age. find the present age.
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Let son's age be x.
Then,father’s current age will be 4x.
Father's age 10 years ago=4x-10=10x-100
4x-10x=-100+10
-6x=-90
-x=-90/6
X=15
If son’s current age is 15,then father's age (4x)=15×4=60…
Then son's age 10 years ago was 15-10=5,
And Father's age was 60-10=50…
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Then,father’s current age will be 4x.
Father's age 10 years ago=4x-10=10x-100
4x-10x=-100+10
-6x=-90
-x=-90/6
X=15
If son’s current age is 15,then father's age (4x)=15×4=60…
Then son's age 10 years ago was 15-10=5,
And Father's age was 60-10=50…
mark as brainliest if it satisfies you ;)
Answered by
1
let son's age be x
so father's age =4x
given:x+10=4x+10/2
2(x+10)=4x+ 10
2x+20=4x+10
20-10=4x-2x
2x = 10
so x = 5
son's present age = x =5 yrs
father's present age=4x= 4 x 5
=20 yrs
so father's age =4x
given:x+10=4x+10/2
2(x+10)=4x+ 10
2x+20=4x+10
20-10=4x-2x
2x = 10
so x = 5
son's present age = x =5 yrs
father's present age=4x= 4 x 5
=20 yrs
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