Father's age is four times the sum of the ages of his two children. After 6 years his age will be twice the sum of the ages of his two children. find the age of father.
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let age of sons be x and y
then age of father=3(x+y)
after 6 years,
age of son's= x+6 and y+6
father's age= 3(x+y)+6
ATQ
=>3(x+y)+6=2(x+6+y+6)
=>3x+3y+6=2x+12+2y+12
=>3x+3y+6=2x+2y+24
=>3x+3y-2x-2y=24-6
=>x+y=18
father's present age= 3(x+y)=3×18
=54 years
father's age after 6 years=
3(x+y)+6=2×18+6
=60 years
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