Question

Father’s age is three times his son’s age. Four years ago, he was 4 times his son’s age. Find their present ages.

Pls answer fast

Answer 1

let age of father be x
and age of son be y
a/q
x = 3y
x -3y = 0. (i)
four years ago
(x-4) = 4(y-4)
x -4 = 4y -16
x - 4y -4 +16 = 0.
x - 4y +12 = 0. (ii)

by eq i and ii
y = 12 and x = 36 yr

Answer 2

Answer:

answer is 12,36 if answer is wrong so am sorry