Math, asked by vipin2448, 1 year ago

Father's age is three times the age of his son. Five years later, father will be two and half time as old as his son. Father age is....

Answers

Answered by Anonymous
0

Answer:

45

Step-by-step explanation:

Let f be the father's age.

Then "father's age is three times the age of his son" tells us that the son's age is f/3.

Five years later, the father's age will be f+5 and the son's age will be f/3 + 5.  We are told that the father's age will be 2.5 = 5/2 times that of his son, so:

f + 5 = 5/2 ( f/3 + 5 )

=> 2f + 10 = 5 ( f/3 + 5 )          [ multiplied by 2 ]

=> 6f + 30 = 5 ( f + 15 )           [ multiplied by 3 ]

=> 6f + 30 = 5f + 75

=> f = 75 - 30 = 45

Answered by prathams87
1

Answer:

Step-by-step explanation:

Let son's age be X

So father's age is 3x

After 5 years

Son's age=X+5

Father's age=3x+5

But given

3x+5=5/2(X+5)

3x+5=(5x+25)/2

6x+10=5x+25

6x-5x=25-10

x=15

Therefore son's current age is 15yrs

So father's age =3×15=45yrs

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