Question

Father's age is three times the sum of ages of his two children. After 5 years, his age will be twice the sum of ages of two children. Find the age of father.

Answer 1

Let the age of father be x years and sum of the ages of his children by y years.
After 5 years,
Father's age = (x + 5) years
Sum of ages of his children = (y + 10) years
From the given information, we have:
x = 3y ...(1)
and x + 5 = 2(y + 10)
x - 2y = 15 ...(2)
From (1) and (2), we have,
3y - 2y = 15 y = 15
x = 3y = 45
Father's age = 45 years

Answer 2

Answer:

let his children age be x

then his father age = 3x

after 5 year his children age will be x+5

and his = (x+5)2

=2x +10

3x=2x+10

3x-2x=10

X=10

3x = 3*10=30

father's age =30