Question

father's age is three times the sum of ages of his two children. After 5 years, his age will be twice the sum of ages of two children. Find the age of father
(use only 2 variables to find the age)

Answer 1

let the age of two children be x and y.
father's present age is 3(x+y).
age of children after 5 years= x+5+y+5
                                        = x+y+10
age of the father after 5 years= 2(x+y+10) or 3(x+y)+5
                        2x+2y+20 = 3x+3y+5
                        2x-3x + 2y-3y= -20+5
                                    -(x+y) = -15
                                     x+y = 15
                  3(x+y) = 3(15)
                            =45
therefore, present age of father is 45.
                                      


















                                    

Answer 2

Answer:

Step-by-step explanation:

Let age of 2children be =X and Y

Father's age 3(x+y)

Age of children after 5years =x+5+y+5= x+y+10

Age of father = 2(x+y+10)=3(x+y)+5

2x+2y+20=3x+3y+5

2x-3x+2y-3y+20-5

-x-y+15 ×(-)

X+y-15=0

x+y=15

Wkt,3(x+y)=3(15)=45