Math, asked by parth8950, 11 months ago

father's age is three times the sum of ages of his two children .after 5 years his age will be twice the sum of ages of two children find the age of father​

Answers

Answered by Lakshya9799
2

Answer:45 years

Step-by-step explanation:

Let age of father be x

And the sum of age of children be y

x=3y 1eq

After 5 years

Age of father will be x+5

And sum of age of children be y+5+5

(x+5)=2(y+10) 2eq

Put x=3y in 2eq

3y+5=2y+20

3y-2y=20-5

y=15

Put in 1eq

x=3y

x=3×15

x=45.ans

Answered by Agamsain
5

\bold{\Large\purple{\boxed{{{Hey \: Mate..!!}}}}}</p><p>

\bold{\Huge\red{\boxed{{{Answer}}}}}

✒ Age is father is 45 years

\bold{\Huge\blue{\boxed{{{Given}}}}}

✒ Father's age is three times the sum of ages of his two children.

✒ After 5 years, his age will be twice the sum of ages of two children.

\bold{\Huge\pink{\boxed{{{To\: Find}}}}}

✒ Age of Father = ?

\bold{\huge\green{\boxed{{{Explanation}}}}}

✏ let the age of father to be 'x' year.

✏ let the age of his 2 sons to be 'y' year.

So,

\boxed{=&gt; x = 3y .........(1)}

⭐ Now, A.T.Q (After 5 years, his age will be twice the sum of ages of two children.)

✏ Age of father

\boxed {\bold{= (x + 5)  \: years}}

✏ Sum of age of his two sons

 \boxed{ \bold{= [y + 2(5)] }}

\boxed{ \bold{= (y + 10) years}}

-----------------------------------------

⭐ Now Again, A.T.Q (After 5 years, his age will be twice the sum of ages of two children.)

\boxed{=&gt; x + 5 = 2}

 \boxed{=&gt; x + 5 = 2y + 20}

\boxed{=&gt; x - 2y = 15 .............(2)}

-----------------------------------------

⭐ From equation (1) and (2)

✏ Putting the value of equation (1) and (2) we get,

\boxed{=&gt; 3y - 2y = 15}

\boxed{=&gt; y = 15 }

✏ Putting the value of (y = 15) equation (1) we get,

\boxed{=&gt; x = 3(15)}

\boxed{=&gt; x = 45}

Hence, the age of father is 45 years.

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