Father's age is three times the sum of ages of his two children After 5 years his age will
be twice the sum of ages of two children. Find the age of father.
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EXPLANATION.
Father age is three times the sum of ages of
his two children.
Let the age of father be = x
Let the age of the sum of ages of his two
children = y
=> x = 3y .....(1)
After 5 years.
the age of father = ( x + 5 ) years.
the age of sum of two children = ( y + 2(5))
years. = ( y + 10 ) years.
His age will be twice the sum of age of
two children.
=> x + 5 = 2 ( y + 10 )
=> x + 5 = 2y + 20
=> x - 2y = 15 ....... (2)
From equation (1) and (2) we get,
=> put the value of equation (1) in (2)
=> 3y - 2y = 15
=> y = 15
put the value of y = 15 in equation (1)
we get,
=> x = 3(15)
=> x = 45
Therefore,
present age of father = x = 45 years.
Answered by
1
Hence the age of father is 45 years.
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