Father's age is three times the sum of ages of his two children After 5 years his age will be twice the sum of ages of two children. Find the age of father.
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Answers
Step-by-step explanation:
Let the age of the sons be x and y.
Given that Father’s age is three times the age of his two children.
Therefore, the present age of the father is 3(x+y)
Now, it is also given, after 5 years, his age will be twice the sum of the ages of his children.
Therefore, after 5 years age of the father will be 3(x+y)+5 and age of the children will be x+5 and y+5.
3(x+y)+5=2(x+5+y+5)
3x+3y+5=2x+10+2y+10
3x+3y+5=2x+2y+20
3x−2x+3y−2y=20–5
x+y=15
Now the age of father was 3(x+y)=3(15)=45 (Putting the value of x+y)
Thus the age of the father is 45
✒ Age is father is 45 years
✒ Father's age is three times the sum of ages of his two children.
✒ After 5 years, his age will be twice the sum of ages of two children.
✒ Age of Father = ?
✏ let the age of father to be 'x' year.
✏ let the age of his 2 sons to be 'y' year.
So,
⭐ Now, A.T.Q (After 5 years, his age will be twice the sum of ages of two children.)
✏ Age of father
✏ Sum of age of his two sons
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⭐ Now Again, A.T.Q (After 5 years, his age will be twice the sum of ages of two children.)
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⭐ From equation (1) and (2)
✏ Putting the value of equation (1) and (2) we get,
✏ Putting the value of (y = 15) equation (1) we get,
Hence, the age of father is 45 years.