father's age is three times the sum of ages of his two children after 5 years his age will be twice the sum of ages of two children find the age of father
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let the of the children be x and y.
let the fathers age be 3(x+y).
age of children after 5 years= x+5+y+5= x+y+10
age of father after five years= 2(x+y+10) or 3(x+y) +5
2x+2y+20 = 3x+3y +5
x+y=15
fathers age = 3*15= 45
let the fathers age be 3(x+y).
age of children after 5 years= x+5+y+5= x+y+10
age of father after five years= 2(x+y+10) or 3(x+y) +5
2x+2y+20 = 3x+3y +5
x+y=15
fathers age = 3*15= 45
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Let age of father = x
Let sum of the ages of the two children be = y
According to the question :-
x = 3y ....(1)
---After 5 years, ages will be----
Father's age = x + 5
Sum of the two children = y + 5 + 5 ( since this "y" comprises ages of two people, the addition needs to be done twice )
According to the question :-
x + 5 = 2 ( y + 10 )
=》 x + 5 = 2y + 20
Due to (1)
=》 3y + 5 = 2y + 20
=》 y = 15
Age of father = 3y = 3 × 15 = 45 years
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