father's age is three times the sum of ages of his two children . After five years , his age will be twice the sum of ages of two children . find the age of father
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x=3(y+z)
x= 3y +3z....(i)
after 5 yrs,
x+5= 2(y+z+10)
x+5= 2y+ 2z+ 20
x-15= 2y +2z....(ii)
sub (ii) frm (i)
x= 45
so father age is 45
x= 3y +3z....(i)
after 5 yrs,
x+5= 2(y+z+10)
x+5= 2y+ 2z+ 20
x-15= 2y +2z....(ii)
sub (ii) frm (i)
x= 45
so father age is 45
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