father's age is three times the sum of ages of his two children.after 5 yrshis age will be twice the sum og ages of the two children.find present age of his father
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HEY DEAR ... ✌
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Let the age of two children be x and y.
father's present age is 3(x+y).
age of children after 5 years= x+5+y+5
= x+y+10
age of the father after 5 years= 2(x+y+10) or 3(x+y)+5
2x+2y+20 = 3x+3y+5
2x-3x + 2y-3y= -20+5
-(x+y) = -15
x+y = 15
3(x+y) = 3(15)
=45
therefore, present age of father is 45.
HOPE , IT HELPS ... ✌
___________________________
Let the age of two children be x and y.
father's present age is 3(x+y).
age of children after 5 years= x+5+y+5
= x+y+10
age of the father after 5 years= 2(x+y+10) or 3(x+y)+5
2x+2y+20 = 3x+3y+5
2x-3x + 2y-3y= -20+5
-(x+y) = -15
x+y = 15
3(x+y) = 3(15)
=45
therefore, present age of father is 45.
HOPE , IT HELPS ... ✌
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