Father 's age is three times the sum of ages of his two children.after 5 years , his age will be twice the sum of ages of two children.find the age of the father.
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say fathers's age is F and Sons age are A and B.
F= (A+B)*3
F+5 = ((A+5)+(B+5))*2
solve for F. - 45 yrs
F= (A+B)*3
F+5 = ((A+5)+(B+5))*2
solve for F. - 45 yrs
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