Question

father's age is three times the sum of Ages of his two children after 5 years his age will be twice the sum of Ages of the two children find the age of the father

Answer 1

HELLO MY DEAR FRIEND

HERE IS UR ANSWER -

LETS TAKE THE AGE OF TWO CHILDREN'S AS - X AND Y
FATHER'S PRESENT AGE - 3(x+y)
THE AGE OF TWO CHILDREN'S AFTER 5 YEARS = 
x+5+y+5 = x+y+10

AFTER 5 YEARS THE FATHERS AGE WILL BE - 3(x+y)+5 
AND THE AGE OF THE TWO CHILDREN'S WILL BE - x+5 and y+5.

=3(x+y)+5 = 2(x+5+y+5)

=3x+3y+5 = 2x+10+2y+10

=3x+3y+5 = 2x+2y+20

=3x-2x+3y-2y = 20–5

=x+y = 15

NOW FATHERS PRESENT 3(x+y)=3×15=45 YEARS. 

THEREFORE, THE FATHERS PRESENT  AGE  = 45 YEARS. 

I HOPE THIS WILL HELP'S U............*-*

# ✌SWETHAPAVS✌# 

Answer 2

$\mathfrak{\huge{Answer:}}$

Let age of father = x

Let sum of the ages of the two children be = y

According to the question :-

x = 3y ....(1)

---After 5 years, ages will be----

Father's age = x + 5

Sum of the two children = y + 5 + 5 ( since this "y" comprises ages of two people, the addition needs to be done twice )

According to the question :-

x + 5 = 2 ( y + 10 )

=》 x + 5 = 2y + 20

Due to (1)

=》 3y + 5 = 2y + 20

=》 y = 15

Age of father = 3y = 3 × 15 = 45 years