Question

Father‘s age is three times the sum of ages of his two sons. Five years later he will be twice the sum of ages of his two sons. Find their present age of the father.

Answer 1

ok this is the present age of the father

Answer 2

Let present ages of son's be "M" and "N" years.

Father‘s age is three times the sum of ages of his two sons.

According to question,

Present age of father = 3(M + N) years ____ (eq 1)

Five years hence,

• Age of sons = (M + 5 + N + 5) years
• Age of father = (M + N) + 5 years

Five years later, he (father) will be twice the sum of ages of his two sons.

According to question,

=> 3(M + N) + 5 = 2(M + 5 + N + 5)

=> 3M + 3N + 5 = 2M + 10 + 2N + 10

=> 3M + 3N + 5 = 2M + 2N + 20

=> 3M - 2M + 3N - 2N = 20 - 5

=> M + N = 15

Put value of (M + N) in (eq 1)

=> Present age of father = 3(15)

=> 45 years.

∴ Present age of Father is 45 years.