Father's age is three times the sum of his two
children's age. After 5 years his age will be twice
the sum of the ages of two children. Find the age of
father.
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Let the age of his first child be 10x
let the age of his 2nd child be 5x
and
let the age of father be 45x
After five years
age of first child be 10x+5x= 15x
age of second child be 5x+5x= 10x
age of father be 45x+5x= 50x
age of father is 50 years
before 5 years - 45=10+5
45 =15 :- three times
After 5 years - 50 = 15+10
50 = 25 :- 2 times
so the age of father is 50 years
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