father's age is three times the sum of the age of two children after 5 years his age will be twice the sum of the ages of two children find the present age of the father
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Let the sum of ages of two sons be x years
Age of man = 3x years
After 5 years age of the man = (3x + 5) years
Sum of ages of two sons = (x + 10) years
Given, (3x + 5) = 2(x + 10)
⇒ (3x + 5) = 2x + 20
⇒ x = 15
Hence 3x = 3(15) = 45
Thus the age of the man(father) is 45 years.
Age of man = 3x years
After 5 years age of the man = (3x + 5) years
Sum of ages of two sons = (x + 10) years
Given, (3x + 5) = 2(x + 10)
⇒ (3x + 5) = 2x + 20
⇒ x = 15
Hence 3x = 3(15) = 45
Thus the age of the man(father) is 45 years.
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