Question

Father's age is three years older than 2 times son's age if sum of the age is 57 years find their

Answer 1

Answer:

Son is 18 years old and father is 39 years old.

Step-by-step explanation:

Gívєn -

Father's age = Three years older than 2 times son's age

Sum of their ages is = 57 years

Tσ fínd -

Their present Ages

Sσlutíσn -

✯ Let the Ages be -

• Son as x
• Father as 2(x) + 3

$\rule{300}{1.5}$

✯ According to the Question -

The sum of their Ages is = 57

$\sf{\implies} \: x + 2(x) + 3 = 57 \\ \sf{\implies} \: x + 2x + 3 = 57 \\ \sf{\implies} \: 3x + 3 = 57 \\ \sf{\implies} \: 3x = 57 - 3 \\ \sf{\implies} \: 3x = 54 \\ \sf{\implies} \: x = \frac{54}{3} \\ \sf{\implies} \: x = 18$

Son is 18 years old

$\rule{300}{1.5}$

✯ Father's present Ages =

$\sf{\implies} \: 2(x) + 3 \\ \sf{\implies} \: 2(18) + 3 \\ \sf{\implies} \: 36 + 3 \\ \sf{\implies} \: 39$

Father is 39 years old.

$\therefore$ Son is 18 years old and father is 39 years old.

Answer 2

Answer:

son's age is 18 years and fathers age is 39

Step-by-step explanation:

father's age = 2xson'sage +3

sum of thier age is 57

so x+2x+3=57

3x=57-3

3x=54

so x is

x=54/3

x=18

so

son's age is 18 years and fathers age is 2x18+3=39