Math, asked by geetanjalibedre5879, 11 months ago

Father's age is three years older than 2 times son's age if sum of the age is 57 years find their

Answers

Answered by Darvince
2

Answer:

Son is 18 years old and father is 39 years old.

Step-by-step explanation:

Gívєn -

Father's age = Three years older than 2 times son's age

Sum of their ages is = 57 years

Tσ fínd -

Their present Ages

Sσlutíσn -

Let the Ages be -

  • Son as x
  • Father as 2(x) + 3

\rule{300}{1.5}

According to the Question -

The sum of their Ages is = 57

\sf{\implies} \: x + 2(x) + 3 = 57 \\ \sf{\implies} \: x + 2x + 3 = 57 \\ \sf{\implies} \: 3x + 3 = 57 \\ \sf{\implies} \: 3x = 57 - 3 \\ \sf{\implies} \: 3x = 54 \\ \sf{\implies} \: x =  \frac{54}{3}  \\ \sf{\implies} \: x = 18

Son is 18 years old

\rule{300}{1.5}

Father's present Ages =

\sf{\implies} \: 2(x) + 3 \\ \sf{\implies} \: 2(18) + 3 \\ \sf{\implies} \: 36 + 3 \\ \sf{\implies} \: 39

Father is 39 years old.

\therefore Son is 18 years old and father is 39 years old.

Answered by pchandrakala
0

Answer:

son's age is 18 years and fathers age is 39

Step-by-step explanation:

father's age = 2xson'sage +3

sum of thier age is 57

so x+2x+3=57

3x=57-3

3x=54

so x is

x=54/3

x=18

so

son's age is 18 years and fathers age is 2x18+3=39

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