Father's is 3 times as old as sum of age of his two sons
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The age of the Father ⬇️⬇️
Age of the first son = x
Age of the second son = y
Age of the Father = 3(x + y)
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Answered by
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Suppose that age of first child is -x
Suppose that age of other child is -y
So....
Age of father- 3(x+y)
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