Father said to his daughter that when, I was of your age you were of age 4 and when ypu will be of my age I will be 79 years old. whose age how much
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Answered by
53
The question may seem tricky but after seeing the solution you might be surprised.
First of all, let us assume that the present age of father & daughter is x and y. Now acc. to question,
Father Daughter
x y
y 4
79 x
Since these are the ages at the same time interval so the age difference after every interval must be the same.
i.e. x - y = y - 4 = 79 - x.
or, x - y = y - 4 ----------- (i)
or, y - 4 = 79 - x ----------- (ii)
Solving these two equations you'll get x = 54 i.e. present age of father and y = 29 i.e. present age of daughter.
First of all, let us assume that the present age of father & daughter is x and y. Now acc. to question,
Father Daughter
x y
y 4
79 x
Since these are the ages at the same time interval so the age difference after every interval must be the same.
i.e. x - y = y - 4 = 79 - x.
or, x - y = y - 4 ----------- (i)
or, y - 4 = 79 - x ----------- (ii)
Solving these two equations you'll get x = 54 i.e. present age of father and y = 29 i.e. present age of daughter.
shriansh2:
thank you so much
Answered by
21
Answer:
how can we understand this answer to 4th class and 5th class student the following answer
Step-by-step explanation:
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