Question

fatherfather's age is 3 times his son's age four years ago he was four times his son's age find their present ages present ages ​

Answer 1

Step-by-step explanation:

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♠ Let the age of father be x

and age of son be y

♣According to Question♣

x = 3y

x - 3y = 0-----------------(i)

•Four years ago,

(x-4) = 4(y-4)

x - 4 = 4y -16

x - 4y - 4 + 16 = 0.

x - 4y + 12 = 0----------(ii)

♦ by equation i and ii

Y = 12yr and X = 36 yr

Hence, Age of father => 36 years and Age of son => 12 years

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Answer 2

Let the age of father be x years and son be y years.

x = 3y

x - 3y = 0⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀...(i)

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Four years ago,

(x-4) = 4(y-4)

x - 4 = 4y -16

x - 4y - 4 + 16 = 0.

x - 4y + 12 = 0⠀⠀⠀⠀⠀⠀⠀⠀...(ii)

From equation (i) and (ii):-

$y = 12~years \\ x = 36~ years$

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Age of father = 36 years

Age of son = 12 years

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