Math, asked by kattaavanti2773, 6 months ago

Fathers age is 3 times the sons age after 8 years fathers age is sons 2 1/2 times and the next 8years father's age is how much time in his sons age

Answers

Answered by chnandini2008
0

Answer:

i hope it is help full ;

Step-by-step explanation:

1. The age of father 8 years ago was 5 times that of his son.

2. 8 years hence his age will be 8 years more than twice the age of son

To Find

Present age of father and son

Solution

Let the present age of father be x

Present age of his son be y

A/c to condition 1 ,

⇒ ( x - 8 ) = 5 ( y - 8 )

⇒ x - 8 = 5y - 40

⇒ x = 5y - 32 ... (1)

A/c to 2nd condition ,

⇒ ( x + 8 ) = 2 ( y + 8 ) + 8

⇒ x + 8 = 2y + 16 + 8

⇒ x - 2y = 16

Sub. (1) here ,

⇒ ( 5y - 32 ) - 2y = 16

⇒ 3y = 48

⇒ y = 16  

Sub. y value in (1) ,

⇒ x = 5(16) - 32

⇒ x = 80 - 32

⇒ x = 48  

So ,

→ Present age of father = 48 years  

→ Present age of son = 16 years  

Similar questions